14x^2+70x-336=7x^2+14x-105

Solution for 14x^2+70x-336=7x^2+14x-105 equation:

14x^2+70x-336=7x^2+14x-105

We move all terms to the left:

14x^2+70x-336-(7x^2+14x-105)=0

We get rid of parentheses

14x^2-7x^2+70x-14x+105-336=0

We add all the numbers together, and all the variables

7x^2+56x-231=0

a = 7; b = 56; c = -231;
Δ = b2-4ac
Δ = 562-4·7·(-231)
Δ = 9604
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9604}=98$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(56)-98}{2*7}=\frac{-154}{14}
=-11
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(56)+98}{2*7}=\frac{42}{14}
=3
$